Help Spinner in FP questions

[GeorgeH]

If xBAM_BAll.Speed = 500 (just an example)
SpL.angularDamping = 0.30 - (2*(xBAM_Ball.Speed -300)/10000))
So
SpL.angularDamping = 0.30 - (2*(500 -300)/10000))
SpL.angularDamping = 0.30 - (2*200)/10000))
SpL.angularDamping = 0.30 - (2*200)/10000))
SpL.angularDamping = 0.30 - (400)/10000))
SpL.angularDamping = 0.30 - 0.4
SpL.angularDamping = 0.26
OK... The idea: the more the ball have the speed, the less will be the angular damping.
You can use a lot of others formulas or criteria.

JP,

The 0.4 in your example should be 0.04. That makes your final result correct. I am guessing you must have tried many formulas before using this one.

George

 

[Popotte]

Not really a lot of formula and I think this one is not the best...
Typo corrected (0.4 -> 0.04)

 

[GeorgeH]

If xBAM_BAll.Speed = 500 (just an example)
SpL.angularDamping = 0.30 - (2*(xBAM_Ball.Speed -300)/10000))
So
SpL.angularDamping = 0.30 - (2*(500 -300)/10000))
SpL.angularDamping = 0.30 - (2*200)/10000))
SpL.angularDamping = 0.30 - (2*200)/10000))
SpL.angularDamping = 0.30 - (400)/10000))
SpL.angularDamping = 0.30 - 0.4
SpL.angularDamping = 0.26
OK... The idea: the more the ball have the speed, the less will be the angular damping.
You can use a lot of others formulas or criteria.

JP,

The 0.4 in your example should be 0.04. That makes your final result correct.

George

Not really a lot of formula and I think this one is not the best...
Typo corrected (0.4 -> 0.04)

The only thing I can suggest that might make it better is to set up a test table that has a kicker aimed at a spinner. You would need to know your minimum and maximum ball speed that is possible on the table. Then set the kicker strength to fire the ball at the minimum ball speed. Then find the best Angular Damping setting that does what you want. Then repeat the same process with the maximum ball speed. Then you would need to figure out a formula that ramps the Angular Damping setting between the two settings.

As it stands, you could delete the times 2 in your formula and substitute 5,000 for the 10,000 and you get the same answer.